how can I write the equation 3(x+2)=y-7 into slope intercept form?
Oops sorry for the late reply.
The slope-intercept form of a linear equation is y=mx+b
This means you have to isolate the dependent variable (y)
To do that you first multiple the 3 into (x+2) which will get you 3x+6
So you would have 3x + 6 = y - 7
Then to isolate "y" just add 7 to both sides.
3x + 6 + 7 = y - 7 + 7
Solving both sides will get you 3x + 13 = y or y = 3x + 13 which is the equation in slope-intercept form.
Comments
Oops sorry for the late
Oops sorry for the late reply.
The slope-intercept form of a linear equation is y=mx+b
This means you have to isolate the dependent variable (y)
To do that you first multiple the 3 into (x+2) which will get you 3x+6
So you would have 3x + 6 = y - 7
Then to isolate "y" just add 7 to both sides.
3x + 6 + 7 = y - 7 + 7
Solving both sides will get you 3x + 13 = y or y = 3x + 13 which is the equation in slope-intercept form.